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The root mean square velocity of one mole of a monoatomic gas having molar mass $M$ is $u_{\mathrm{r}, \mathrm{m} . \mathrm{s}} .$ The relation between the average kinetic energy $(E)$ of the gas and $u_{\text {r.m. }}$ is
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\mathrm{s}}$. This can be represented as: \[u_{\mathrm{r}, \mathrm{m} . \mathrm{s}} = \sqrt{u}\] Show more…
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The root mean square velocity of one mole of a monoatomic gas having molar mass $\mathrm{M}$ is $u_{\mathrm{rms}}$. The relation between the average kinetic energy (E) of the gas and $u_{r m}$ is (a) $\mathrm{u}_{\mathrm{rm}}=\sqrt{(3 \mathrm{E} / 2 \mathrm{M})}$ (b) $\mathrm{u}_{\mathrm{ms}}=\sqrt{(2 \mathrm{E} / 3 \mathrm{M})}$ (c) $\mathrm{u}_{\mathrm{mas}}=\sqrt{(2 \mathrm{E} / \mathrm{M})}$ (d) $u_{\operatorname{me}}=\sqrt{(E / 3 M)}$
The root mean square velocity of one mole of a monoatomic gas having molar mass $\mathrm{M}$ is $\mathrm{u}_{\mathrm{rms}}$ - The relation between the average kinetic energy (E) of the gas and $\mathrm{u}_{\mathrm{rms}}$ is: (a) $\mathrm{u}_{\mathrm{rms}}=\sqrt{(3 \mathrm{E} / 2 \mathrm{M})}$ (b) $\mathrm{u}_{\mathrm{mas}}=\sqrt{(2 \mathrm{E} / 3 \mathrm{M})}$ (c) $\mathrm{u}_{\mathrm{rms}}=\sqrt{(2 \mathrm{E} / \mathrm{M})}$ (d) $\mathrm{u}_{\mathrm{mas}}=\sqrt{(\mathrm{E} / 3 \mathrm{M})}$
The root mean square velocity of one mole of a monoatomic gas having molar mass $\mathrm{M}$ is Urms. The relation between the average kinetic energy (E) of the gas and Urms is a. $\mathrm{Urms}=\sqrt{(3 \mathrm{E} / 2 \mathrm{M})}$ b. Urms $=\sqrt{(2 \mathrm{E} / 3 \mathrm{M})}$ c. $\mathrm{Urms}=\sqrt{(2 \mathrm{E} / \mathrm{M})}$ d. $\mathrm{Urms}=\sqrt{(\mathrm{E} / 3 \mathrm{M})}$
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