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University of Maine

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Problem 64

The scene below represents a mixture of A2 and B2 before they react to form $\mathrm{AB}_{3}$

(a) What is the limiting reactant?

(b) How many molecules of product can form?

Answer

a. B2 is limiting (green). b. 4 molecules AB3

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## Discussion

## Video Transcript

limiting re agent is the initial reactant that produces thes smaller quantity of product. It's important to go through the streaky a metric calculations rather than just looking at inspection, because it's not always the reactive that is a present in smaller quantities. So we have to take into account our strike you metric lee equivalent ratios. So if we look at this example where we say that the blue molecules air a to and the green molecules or be too, and the reaction we're looking at is a two plus B two makes a B three, we need to balance the equation to look at our story que metric equations. And so to balance it was it to hear and a three here. And so this gives us our mole ratios for those. So if we have three moles of A to, we should figure out how many moles A B will form 83 and we do that using you creation from the balanced equation, the ratios. Chris tells us that for every one more of a to we'll form two moles of a B three. So if I have three moles A to I'll produce 2 to 1 ratio or six moles of product. If I have six malls speed too, I can calculate how many moles of a B I should produce from that. The equation tells me for every three moles be to, I should produce two moles of a B three. If I have six moles, be to well produced two moles, a B three for every three moves be to or formals of product. So when we compare are two amounts of products, we can see that B two produces less, So that means that be too, even though there's more of it is the limiting re agent and it should produce four moles of product.

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