00:01
All right, i've drawn beforehand here, the four beakers filled with the solution.
00:06
And i've represented ha by both red and blue, and the a minus is the only red.
00:15
So if we count it up here, the first one, h .a.
00:19
Equals seven, and a minus equals three.
00:22
And this one, h .a.
00:24
Equals three, a minus equals seven.
00:26
The third one, h .a.
00:28
Equals 5, a minus equals 5.
00:30
Fourth one, h .a.
00:31
Equals 3 and a minus equals 3.
00:36
And so to answer this first question, which solution has the greatest buffer capacity? we can take a look here at the henderson -hasselbach equation.
00:46
And when a -minus equals ha, then the ph equals the p -k -a.
00:52
And the reason for that is because when you take the log of 1, so if these numbers, a minus and h .a.
00:58
Are the same.
01:00
Then that's 1 over 1 essentially.
01:03
And if you take the log of 1, that equals 0.
01:05
And then the p .a equals the ph.
01:09
So if we go back here and take a look at these, the third and the fourth one right here, they have even numbers.
01:16
And so they would have the greatest buffer capacity.
01:20
Now the question is, which one out of the two has the better buffer capacity? and the answer is the third one, because it has a greater concentration inside of it.
01:34
And so since there's more molecules, there's more molecules available to neutralize any added acid or base...