Question
The second-order rate constant for the decomposition of HI at $750^{\circ} \mathrm{C}$ was given in Problem 13.81. At $2.5 \times 10^{3}$ minutes after a particular experiment had begun, the HI concentration was equal to $4.5 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1}$. What was the initial molar concentration of HI in the reaction vessel?
Step 1
We do this by multiplying the given time by 60 (since there are 60 seconds in a minute): \[2.5 \times 10^{3} \, \text{minutes} \times 60 \, \text{s/min} = 1.5 \times 10^{5} \, \text{seconds}\] Show more…
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