00:01
Chapter 14, question 122.
00:04
So i'm not going to read the entire question, but let's go one by one.
00:09
They give us a reaction over here.
00:12
Ch4 plus cl2, and this reaction is very slow in the absence of light.
00:19
With light, however, chlorine with the presence of light, you get two chlorine radicals.
00:27
So they don't show this as radicals over here, but what we normally see is chlorine fits an electron.
00:37
This single electron means that's a radical and this highly active.
00:43
So once the chlorine atoms are generated, they can catalyze the reaction of ch4 and cl2, according to the proposed mechanism.
00:51
They're given two reactions, reactions three and four.
00:55
And ch4 is becoming a ch3 radical with the chlorine catching up one of the hydrogens.
01:05
And ch3 radical is catching one of the chlorines and yielding a chlorine radical.
01:13
So what happens is this, this chlorine radical then again goes into the reaction with ch4 and chlorine then again goes.
01:22
So this is a typical catalyst where you see one of the molecules or atoms in this case, in the reactants and in the end of the products, so that can react again.
01:37
The enthalpy chains and activation energies for these two reactions are tabulated as follows.
01:43
By using the bond enthalpy for cl2 in table 8 .4, though i believe they want to say table 8 .3, because 8 .4 does not have anything with chlorine.
01:55
Determine the longest wavelength of light that is energetic enough to cause reaction to to occur.
02:02
So for this reaction two to occur, we need this light.
02:07
And what we need to do is if you can recall the formula, energy equals to h, c or lambda.
02:21
They're asking us the wavelength, lambda over here.
02:25
So let's remember what they were.
02:28
Energy is going to be in jules and h is planx constant.
02:40
That is 6 .626 times 10 to the power of negative 224 joules.
02:55
Second, c is going to be three times 10 to the power of 8 meters per seconds.
03:11
And we need to find the lambda using these two values.
03:16
And we also need the energy.
03:18
So let's look at the energy for chlorine.
03:23
It should be over here.
03:25
242.
03:26
This is kilojoules per moles.
03:28
So i'm going to adjust this.
03:30
As if you want jules.
03:35
So i'm going to multiply this by a thousand.
03:42
And if you solve for lambda, what you're going to get is units of meters, but you want to convert that to nanometers with a conversion factor of 10 to the power of negative 9.
04:00
So if you solve this equation, this equation over here, you're going to find lambda to be 494 nanometers.
04:15
So that was a.
04:20
And at b, using the data tabulated here, sketch a quantitative energy profile for the catalyzed reaction representing 3 and 4.
04:33
So we can do that, but let's make it a little bit more detailed by using the chapter the c2 by using bone energy bond etatopils estimate where the reactants should be placed on your diagram so let's just draw everything that is possible to be able to solve b and c together okay there's a graph and this is energy versus the reaction coordinate so if i want to look at the energy for ch4, i want to look at the entelope for ch.
05:24
This is 413.
05:28
So if i multiply this number, let's solve it over here.
05:35
413 times 4.
05:41
What we're going to get is 1 ,652.
05:51
So this is going to be energy of ch4.
05:57
Now, what else do we need? we don't have the energy for chlorine because there's no bond.
06:05
Over here, we have a ch3.
06:07
So for ch3, 413, multiply by 3.
06:16
And then we're going to add cl2, which is 242.
06:26
This is going to be equal to 100239.
06:33
These are in kilojoules per moles.
06:46
So now we can draw these two of them easily.
06:50
And let's write this was again for ch3 plus cl2.
07:01
So this first one is at a higher energy.
07:06
So let's start it from here.
07:09
And over here you can see the overall enthalpy is going to be a positive value so this is going to be endothermic and energy of activation is 17 so let's say i start from here go up 17 come down to a positive value so what we start with is going to be 100 1 ,652 plus 17 1669 this value plus 4 1 ,600 56.
07:55
Now this other value starts from lower and it goes up for 4 and comes down 109.
08:09
So it starts with thousand to a hundred thirty nine goes up to thousand to a hundred forty three and comes down to 1 ,130...