Question
The sewage outlet of a house constructed on a slope is $6.59 \mathrm{~m}$ below street level. If the sewer is $2.16 \mathrm{~m}$ below street level, find the minimum pressure difference that must be created by the sewage pump to transfer waste of average density $1000.00 \mathrm{~kg} / \mathrm{m}^{3}$ from outlet to sewer.
Step 1
This can be found by subtracting the height of the sewer from the height of the sewage outlet. This gives us: \[ h = h_{1} - h_{2} = 6.59 \, m - 2.16 \, m = 4.43 \, m \] Show more…
Show all steps
Your feedback will help us improve your experience
Matthew Baker and 92 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
The scwage outlet of a house constructed on a slope is $6.59 \mathrm{~m}$ below street level. If the sewer is $2.16 \mathrm{~m}$ below street level, find the minimum pressure difference that must be created by the sewage pump to transfer waste of average density $1000.00 \mathrm{~kg} / \mathrm{m}^{3}$ from outlet to sewer.
The sewage outlet of a house constructed on a slope is 6.59 $\mathrm{mbe}$ - low street level. If the sewer is 2.16 $\mathrm{m}$ below street level, find the minimum pressure difference that must be created by the sewage pump to transfer waste of average density 1000.00 $\mathrm{kg} / \mathrm{m}^{3}$ from outlet to sewer.
The sewer outlets of a house constructed on a slope are $8.16 \mathrm{~m}$ below street level. If the sewer is $2.08 \mathrm{~m}$ below street level, find the minimum pressure differential that must be created by the sewage pump to transfer waste of average density $926 \mathrm{~kg} / \mathrm{m}^{3}$
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD