Question
The shortest distance from the point $(4,2)$ to the circle $x^{2}+y^{2}-10 x-4 y-7=0$ is(a) 1(b) 5(c) 6(d) 11
Step 1
The center of the circle is given by $(h, k) = (g, f)$ where $g$ and $f$ are the coefficients of $x$ and $y$ in the equation of the circle. In this case, the center is at $(5, 2)$. Show more…
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