00:01
Here we have a square and we're told that the length of the side is changing at a rate of two meters per second.
00:10
What we want to know is how fast the area is changing when the side length is 10 meters.
00:25
Okay.
00:26
So we're going to use our area formula.
00:30
Formula for the area of a square is a equals side squared.
00:36
We're going to go ahead and differentiate that.
00:42
So we have d -a -d -t is equal to 2 -s -d -t.
00:49
And then we're going to plug in the things that we know.
00:53
We're trying to find d -a -d -t.
00:58
Two is constant.
00:59
S is 10 and d -s -d -t is 2.
01:03
So dadt is equal to, well, 10 times 2 is 20 times 2 is 40, 40 meters squared per second.
01:17
Okay, so next we want to know what is dadt when the side is 20 meters.
01:29
Okay, so we can use this formula here that already differentiated.
01:35
We're going to say, well, d80t is equal to 2 times 20 times 2.
01:48
And when the side length is 20, d80t is going to be equal to 80 meter squared per second...