Question
The sixth term of an A.P. is equal to 2 . The value of the common difference of the A.P. which makes the product $a_{1} a_{4} a_{5}$ greatest, is(A) $\frac{8}{5}$(B) $\frac{2}{3}$(C) $\frac{3}{5}$(D) $\frac{3}{4}$
Step 1
Given that the sixth term is 2, we can write $a_6 = a_1 + 5d = 2$. Show more…
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