00:01
All right, so let's let p of n plus 1 be equal to b, p of n divided by a plus p of n, with p of zero being greater than zero.
00:18
So then if p of n converges to l, we then take limits, and we can then multiply and get l a plus l is equal to bl, giving us a -l plus l squared equals b -l, giving us l squared plus a minus b times l -equal, and then l times l plus a -minus b equals zero.
00:48
So l -equals zero, or l is equal to b minus a.
00:56
And then since a plus p of n is greater than zero, we get that p of m plus 1 is equal to b, p of n, which over a plus p of n, which is less than b, p of n over a.
01:13
So we get that p of n plus n plus 1 is less than b, p of n over a.
01:14
So we get that p of n plus 1 is less than b over a p of n.
01:24
And then if a, if a, and plus 1 is less than b over a p of n...