The formula for the mass moment of inertia of a rod about its end is $\frac{1}{3}ml^2$. Here, m is the mass of the rod and l is the length of the rod. Given that the mass m is 6 kg and the length l is 2 m, we have:
\[I_A = \frac{1}{3} \times 6 \times 2^2 = 8 \,
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