00:01
So, in this question, we have theta equals to 0 .8t minus t squared by 20.
00:09
So, differentiating it with respect to time, we get theta dot that will be equals to 0 .8 minus t, t by 10.
00:17
Okay? and again, differentiating it with respect to time, we get theta double dot that will be equals to minus 1 by 10.
00:23
And also we have r equals to 1 .6 minus 0 .2t.
00:29
Okay? at t equals to 0, we have position r equals to 1 .6.
00:33
So with respect to time, we can write this position vector.
00:36
So from here, we get after differentiating with respect to time, r dot, that will be equals to 0 .2, and r double dot will be equals to 0 because this value is constant.
00:47
So now, the most general form of the velocity vector in two -dimensional motion is given by v vector equals to r dot, r -cap, plus r -theta dot, theta cap so substituting the values obtained from here to here in this equation we get v vector equals to r dot is minus 0 .2 and r cap plus r is equals to r theta dot so after substituting this value and we get 0 .32 theta cap okay so this is the velocity vector answer.
01:32
Okay.
01:32
So this is the velocity of the particle in the vector form.
01:36
And the magnitude of this velocity will be equal to v .2 .3 .3 meter per second...