Question
The small piston of a hydraulic lift (Fig. P15.6) has a cross-sectional area of $3.00 \mathrm{cm}^{2},$ and its large piston has a crosssectional area of $200 \mathrm{cm}^{2}$ What downward force of magnitude $F_{1}$ must be applied to the small piston for the lift to raise a load whose weight is $F_{g}=15.0 \mathrm{kN} ?$
Step 1
00 \, \text{cm}^2$ and the large piston has a cross-sectional area of $A_2 = 200 \, \text{cm}^2$. The force on the large piston is $F_2 = 15.0 \, \text{kN}$. Show more…
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