1 \, \mathrm{W/cm^2} \). To work with standard units, we convert this to \( \mathrm{W/m^2} \). Since \( 1 \, \mathrm{cm^2} = 10^{-4} \, \mathrm{m^2} \), we have:
\[
S = 0.1 \, \mathrm{W/cm^2} \times \frac{1 \, \mathrm{cm^2}}{10^{-4} \, \mathrm{m^2}} = 0.1 \times
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