Question
The sole of a man's size-10 shoe is around $11.0$ in. by $4.00$ in. Determine the gauge pressure under the feet of a 200-lb man standing upright. Give your answer in both lb/in. $^{2}$ and Pa. [Hint:$1.00 \mathrm{lb} / \mathrm{in}^{2}=6895 \mathrm{~Pa}$. Check your work using $1.00 \mathrm{in} .^{2}=6.45 \times$$10^{-4} \mathrm{~m}^{2}$ and $\left.1.00 \mathrm{lb}=4.448 \mathrm{~N} .\right]$
Step 1
The area (A) of a rectangle is given by the formula A = length x width. In this case, the length of the shoe is 11 in. and the width is 4 in. So, the area of the sole of the shoe is A = 11 in. x 4 in. = 44 in.$^{2}$. Show more…
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