The solid cylindrical rod $B C$ is attached to the rigid lever $A B$ and to the fixed support at $C .$ The vertical force $P$ applied at $A$ causes a small displacement $\Delta$ at point $A$. Show that the corresponding max imum shearing stress in the rod is
\[\tau=\frac{G d}{2 L a} \Delta\]
where $d$ is the diameter of the rod and $G$ is its modulus of rigidity.