Question
The solid lies between planes perpendicular to the $x$ -axis at$x=-1$ and $x=1 .$ The cross-sections perpendicular to the $x$ -axisbetween these planes are squares whose diagonals run from thesemicircle $y=-\sqrt{1-x^{2}}$ to the semicircle $y=\sqrt{1-x^{2}}$
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This means that the length of the diagonal of the square is the distance between these two points. Show more…
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The solid lies between planes perpendicular to the $x$ -axis at $x=-1$ and $x=1 .$ The cross-sections perpendicular to the $x$ -axis between these planes are squares whose bases run from the semicircle $y=-\sqrt{1-x^{2}}$ to the semicircle $y=\sqrt{1-x^{2}}$
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The solid lies between planes perpendicular to the $x$ -axis at $x=-1$ and $x=1 .$ The cross-sections perpendicular to the $x$ -axis between these planes are squares whose diagonals run from the semicircle $y=-sqrt{1-x^{2}}$ to the semicircle $y=sqrt{1-x^{2}}$
The solid lies between planes perpendicular to the $x$ -axis at $x=-1$ and $x=1 .$ The cross-sections perpendicular to the $x$ -axis between these planes are squares whose bases run from the semi- circle $y=-\sqrt{1-x^{2}}$ to the semicircle $y=\sqrt{1-x^{2}}$
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