Question
The solid lies between planes perpendicular to the $x$ -axis at $x=0$and $x=4 .$ The cross-sections perpendicular to the axis on the interval $0 \leq x \leq 4$ are squares whose diagonals run from the parabola $y=-\sqrt{x}$ to the parabola $y=\sqrt{x}$ .
Step 1
The diagonal runs from the parabola $y=-\sqrt{x}$ to the parabola $y=\sqrt{x}$. The length of the diagonal is the difference between the $y$-coordinates of these two points, which is $\sqrt{x}-(-\sqrt{x})=2\sqrt{x}$. Show more…
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