00:02
Alright, so this question is about the solubility of silver fluoride and we know that when silver chloride when it's associated in solution we have a silver hymn and c .m.
00:21
Okay, so the solubility products will be a g plus multiply by c .m .m .us concentration.
00:34
Now we we are told that the solidity has at 25 degrees celsius is 1 .33 times 10x5 more liters.
00:48
So if it dissociates, it's going to be, but the solvility is 1 .1 .3 and 10 square 5 more philiter, that means we'll have 1 .33, that's 10x0 minus 5 more liter, and 1 .33 plus number five more quality of each of them so the ksp then will be equals to 1 .3 times times times per minus five more per liter square with a squares and this should be 1 .7 6 times power minus 10 so we have to determine the solidity products at 50 degrees celsius at 50 degrees celsius.
01:57
So we are going to use this equation on k2, which is ksp 2.
02:05
We can call this ksp 1.
02:08
But ksp 1 is equals to negative delta h of reaction over 1 over 2 to minus 1 over 2 1.
02:24
So, this will then the link ksp2.
02:33
From the ksp1 is 176, 10 to 5 minus 10.
02:41
It's supposed to say.
02:42
We are given the delta h of reaction to be 65 .7 below, minus 65 .7 million jose per more...