The solubility of benzoic acid $\left(\mathrm{HC}_{7} \mathrm{H}_{5} \mathrm{O}_{2}\right)$
is $0.34 \mathrm{g} / 100 \mathrm{mL}$ in water at $25^{\circ} \mathrm{C}$ and is $10.0 \mathrm{g} / 100 \mathrm{mL}$ in
benzene $\left(\mathrm{C}_{6} \mathrm{H}_{6}\right)$ at $25^{\circ} \mathrm{C}$. Rationalize this solubility behavior. (Hint: Benzoic acid forms a dimer in benzene.) Would benzoic acid be more or less soluble in a 0.1-M NaOH solution than it is in water? Explain.