00:01
Looking at the first part of this question, we need to recall that the solubility of co2 can be calculated as kh multiplied by the partial pressure or the vapor pressure of co2.
00:12
Now looking at the information that we have right here, to determine this kh which is just equal to the concentration, concentration is equal to number of moles divided by the volume, n number of moles is equal to mass divided by the molar mass.
00:27
So we are looking at a concentration that is equal to the mass divided by the molar mass multiplied by the volume.
00:34
So looking at this, we are looking at 7 .24 divided by 44 grams per more, and we multiply this by a hundred milliliter that will then convert into liters barring dividing by a thousand.
00:47
This gives us a concentration that is equal to 5 .47, 5 .45 by 10 to the power negative 2 .2.
00:57
In units of moles per liter.
01:00
Therefore, the solubility of co2 is going to be 5 .45 by 10 to the 0 .9 % to the 0 .45 % multiplied by 4 atmosphere.
01:08
And then we are looking at this being equal to 0 .218 in units of moles per liter.
01:20
So looking at the solubility, the mass or rather the volume of salt drink converting this into oars to militer...