Question

The solubility of $\mathrm{N}_2$ in blood at $37^{\circ} \mathrm{C}$ and at a partial pressure of 0.80 atm is $5.6 \times 10^{-4} \mathrm{mol} / \mathrm{L}$. A deep-sea diver breathes compressed air with the partial pressure of $\mathrm{N}_2$ equal to 4.0 atm . Assume that the total volume of blood in the body is 5.0 L . Calculate the amount of $\mathrm{N}_2$ gas released (in liters at $37^{\circ} \mathrm{C}$ and 1 atm ) when the diver returns to the surface of the water, where the partial pressure of $\mathrm{N}_2$ is 0.80 atm .

   The solubility of $\mathrm{N}_2$ in blood at $37^{\circ} \mathrm{C}$ and at a partial pressure of 0.80 atm is $5.6 \times 10^{-4} \mathrm{mol} / \mathrm{L}$. A deep-sea diver breathes compressed air with the partial pressure of $\mathrm{N}_2$ equal to 4.0 atm . Assume that the total volume of blood in the body is 5.0 L . Calculate the amount of $\mathrm{N}_2$ gas released (in liters at $37^{\circ} \mathrm{C}$ and 1 atm ) when the diver returns to the surface of the water, where the partial pressure of $\mathrm{N}_2$ is 0.80 atm .
 
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Chemistry
Chemistry
Raymond Chang, Jason… 14th Edition
Chapter 12, Problem 38 ↓
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The solubility of $\mathrm{N}_2$ in blood at $37^{\circ} \mathrm{C}$ and at a partial pressure of 0.80 atm is $5.6 \times 10^{-4} \mathrm{mol} / \mathrm{L}$. A deep-sea diver breathes compressed air with the partial pressure of $\mathrm{N}_2$ equal to 4.0 atm . Assume that the total volume of blood in the body is 5.0 L . Calculate the amount of $\mathrm{N}_2$ gas released (in liters at $37^{\circ} \mathrm{C}$ and 1 atm ) when the diver returns to the surface of the water, where the partial pressure of $\mathrm{N}_2$ is 0.80 atm .
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The solubility of N2 in blood at 37°C and at a partial pressure of 0.80 atm is 5.6 x 10^24 mol/L. A deepsea diver breathes compressed air with the partial pressure of N2 equal to 4.0 atm. Assume that the total volume of blood in the body is 5.0 L. Calculate the amount of N2 gas released (in liters at 37°C and 1 atm) when the diver returns to the surface of the water, where the partial pressure of N2 is 0.80 atm.


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Transcript

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00:01 This is question 38 from chapter 13 and it's about dye nitrogen in the blood of the solubility and we are trying to see what is the pressure or the volume when diver is coming up to the surface.
00:19 So they said the dye nitrogen is equal to 4 .0 atmosphere and so the first thing we're going to do is actually use sulfur, use henry's constant.
00:36 Okay, so they do give us henry's constant.
00:43 I'm going to have this k.
00:45 That's what it stands for.
00:46 K is equal to.
00:47 And they give us a 5 .6 times 10 to negative 4 moles per liter.
01:01 And they also give us a pressure of 0 .80.
01:22 And that is going to come out to be 7 times 10 to negative 4 liters times atmosphere.
01:47 And we're going to take that and multiply that with the 4 .0 that they say it's equal to.
01:54 So 7 times 10 to negative 4 times 4 atmospheres pressure.
02:11 That is going to be equal to 2 .8 times 10 to negative 4th.
02:36 Okay, after that we have to find the di - nitrogen gas, so we have to find the number of moles of the gas dissolved.
02:45 So i'm going to take the 2 .8 and we are going to multiply that by the cell.
03:02 It was 5 liters.
03:04 So 5 .0 liters.
03:10 And that comes out to be 0 .028 moles.
03:28 Okay, now it's, i got ahead, just up .028, spoiler alert.
03:40 I'm going to basically half that, so it shouldn't have been 1, 14, my bad, so moles...
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