The sonar unit on a boat is designed to measure the depth of fresh water $\left(\rho=1.00 \times 10^{3} \mathrm{~kg} / \mathrm{m}^{3}, B_{\mathrm{ad}}=2.20 \times 10^{9} \mathrm{~Pa}\right) .$ When the
boat moves into seawater $\left(\rho=1025 \mathrm{~kg} / \mathrm{m}^{3}, B_{\mathrm{ad}}=2.37 \times 10^{9} \mathrm{~Pa}\right)$, the
sonar unit is no longer calibrated properly. In seawater, the sonar unit indicates the water depth to be $10.0 \mathrm{~m}$. What is the actual depth of the water?