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University of Washington

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Problem 77 Medium Difficulty

The sound intensity $50 \mathrm{m}$ from a wailing tornado siren is $0.10 \mathrm{W} / \mathrm{m}^{2} .$ What is the sound intensity level $300 \mathrm{m}$ from the siren?

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we are given this question. We are given that the intensity I 0.1 watts per meter square when it is 50 m away from the siren, we need to find intensity. All right, some intensity level. Mhm at Jared meters away. Uh huh. From the siren. Alright, So we first we'll be using Uh huh. I to give up. I won because we before we need to find before we want to find a sound intensity level. We first need to find a, uh intensity. Okay, at that point at 300 m away from the siren, So I to divide by one is our one by by our two square. Okay, So I to is equal to I one times are one divide by our two square. So 0.1 times 15 develop my Children, then square. Get 2.8 times. Tend to the ministry what's per meter square king And then for the sound intensity level you'll be using radar equals two 10 not based 10 I, if ever I know. Yeah. So the sound intensity level is equal to 10 times long base 10, 2.8 times 10 to the ministry divide by bye bye. One times 10 to the minus trough calculate days. You get 94 decibels. Okay, so this is the answer for this question, and that's all.