Question
The spacing in a crystal lattice can be measured very accurately by X-ray diffraction, and this provides one way to determine Avogadro's number. One form of iron has a body-centered cubic lattice, and each side of the unit cell is 286.65 pm long. The density of this crystal at $25^{\circ} \mathrm{C}$ is $7.874 \mathrm{~g} / \mathrm{cm}^3$. Use these data to determine Avogadro's number.
Step 1
The side length of the unit cell is given as 286.65 pm. 1 pm = \(1 \times 10^{-12}\) m = \(1 \times 10^{-10}\) cm. Thus, \[ 286.65 \, \text{pm} = 286.65 \times 10^{-10} \, \text{cm} = 2.8665 \times 10^{-8} \, \text{cm}. \] Show more…
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The spacing in a crystal lattice can be measured very accurately by X-ray diffraction, and this provides one way to determine Avogadro's number. One form of iron has a body-centered cubic lattice, and each side of the unit cell is 286.65 pm long. The density of the crystal at 25 °C is 7.874 g/cm3. Use this data to determine Avogadro's number.
Iron crystallizes in a body-centered cubic lattice. The cell length as determined by X-ray diffraction is $286.7 \mathrm{pm}$. Given that the density of iron is $7.874 \mathrm{~g} /$ $\mathrm{cm}^{3},$ calculate Avogadro's number.
Iron crystallizes in a body-centered cubic lattice. The cell length as determined by X-ray diffraction is $286.7 \mathrm{pm}$. Given that the density of iron is $7.874 \mathrm{g} / \mathrm{cm}^{3},$ calculate Avogadro's number.
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