Question
The specific heat capacity of benzene $\left(\mathrm{C}_{6} \mathrm{H}_{6}\right)$ is $1.74 \mathrm{J} / \mathrm{g} \cdot \mathrm{K} .$ What is its molar heat capacity (in $\mathrm{J} / \mathrm{mol} \cdot \mathrm{K}) ?$
Step 1
The molecular formula of benzene is C6H6, so its molar mass is: (6 * 12.01 g/mol for C) + (6 * 1.01 g/mol for H) = 72.06 + 6.06 = 78.12 g/mol Now, we can find the molar heat capacity by multiplying the specific heat capacity by the molar mass: Show more…
Show all steps
Your feedback will help us improve your experience
Adam Wade and 54 other Chemistry 101 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
The specific heat capacity of benzene $\left(\mathrm{C}_{6} \mathrm{H}_{6}\right)$ is 1.74 J/g \cdot K. What is its molar heat capacity (in $\mathrm{J} / \mathrm{mol} \cdot \mathrm{K}) ?$
The specific heat capacity of benzene, $\mathrm{C}_{6} \mathrm{H}_{6},$ is 1.74 J $\mathrm{g}^{-1} \mathrm{~K}^{-1}$. Calculate its molar heat capacity.
The specific heat capacity of benzene, $\mathrm{C}_{6} \mathrm{H}_{6}$, is $1.74 \mathrm{Jg}^{-1} \mathrm{~K}^{-1}$. What is its molar heat capacity (in $\mathrm{J} \mathrm{mol}^{-1} \mathrm{~K}^{-1}$ )?
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD