Question
The specific rotation of (S)-2-butanol is $+13.5$. If $1.00 \mathrm{~g}$ of its enantiomer is dissolved in $10.0 \mathrm{~mL}$ of ethanol and placed in a sample cell with a length of $1.00 \mathrm{dm}$, what observed rotation do you expect?
Step 1
First, we need to find the concentration of the enantiomer in the solution. To do this, we need to find the number of moles of the enantiomer and divide it by the volume of the solution in liters. Show more…
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The enantiomeric excess and observed specific rotation of a mixture containing $6 \mathrm{~g}$ of $(+)-2$ -butanol and $4(\mathrm{~g})$ of $(-)-2$ -butanol are respectively (If the specific rotation of enantiomerically pure $(+)-2$ -butanol is $+13.5$ units) (a) $80 \%$, $+2.7$ unit (b) $20 \%,-27$ unit (c) $20 \%,+2.7$ unit (d) $80 \%$, $-27$ unit
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