00:01
For this problem on the topic of particle physics, we have a positive kion, which is a bound state of an up quark and an anti -down quark, decaying into an anti -meon and a muon neutrino, which is a process that is mediated by a w plus boson.
00:16
Now we want to use relativistic methods and solve for various properties of the kion, muon, and neutrino.
00:23
So firstly, for part a, by energy conservation, we have the mass of the kion mk times c -square.
00:31
Is equal to gamma times the mass of the mu on mmu times c squared plus the energy of the neutrino e new.
00:52
For part b by momentum conservation, we know the initial momentum is zero.
00:58
The neutrino is treated as massless, so we have the momentum of the neutrino equal to its energy divided by c and momentum conservation gives gamma m mu times v equal to e nu over c.
01:25
For part c we want the speed of the muon.
01:38
We'll combine the engine momentum equation from a and b, which gives us m k c squared equal to gamma m mu c squared plus gamma gamma m mue times v times c next we'll substitute for sigma and then for gamma and finally solve for v so sigma is equal to gamma into one plus v over c which is one over the square root of one minus v squared over c squared into 1 plus v over c.
02:26
And so by rearranging we get v to be c times sigma squared minus 1 over sigma squared plus 1.
02:45
For part d, sigma is equal to the mass of the k on over the mass of the muon, which would be given values is 493 .0 .7 mega -electro.
03:01
Volts by c squared divided by 105 .7 mega electron volts by c squared, which is a ratio of 4 .671.
03:25
For part e, we want e mu, and we'll use the results of c and d to find v, and we get v is equal to c into 4 .671 squared minus 1 divided by 4 .671 squared plus 1...