00:01
So we know the torque to be equaling, this would be the torque equaling n.
00:13
This n would be the number of turns in a loop multiplied by i, the current, through the loop, times the cross -sectional area of a turn multiplied by the magnitude of the magnetic field times sign of theta.
00:25
We know here sign of theta is going to be equal to 1 because theta is equaling 90 degrees, sign of 90 degrees is equaling 1.
00:33
And so we can then say that the torque is equaling 50 turns multiplied by the current of 50 .0 micro amps.
00:45
So 50 times 10 to the negative 6th amperes, multiplied by the cross -sectional area, pi times r squared.
00:53
The radius here is 1 .5 centimeters, so 0 .1 .50 meters, quantity squared, multiplied by half a tesla.
01:05
And then we can say that then the torque for part a is equaling 8 .83 times 10 to the negative 7th newton meters.
01:16
This would be our final answer for part a.
01:20
For part b then, we can find the spring constant.
01:26
And we know that the torque is equaling a force times a radius...