Question
The square root of $\frac{x^{2}}{y^{2}}-\frac{y^{2}}{x^{2}}-2\left(\frac{y}{x}-\frac{x}{y}_{i}\right)+2 i-1$ is(a) $\pm\left(\frac{x}{y}+i\left(\frac{y}{x}+1\right)\right)$(b) $\pm\left(\frac{x}{y}-\frac{y}{x}+i\right)$(c) $\pm\left(\frac{x}{y}-i\left(\frac{y}{x}+1\right)\right)$(d) $\pm\left[\left(\frac{x}{y}-\frac{y}{x}\right) i+1\right]$
Step 1
We can rewrite this expression as $\frac{x^{2}}{y^{2}}-\frac{y^{2}}{x^{2}}+2i\left(1-\frac{y}{x}-\frac{x}{y}\right)-1$. Show more…
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