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The standard heat of formation of PI3(s) is -24.7 kJ/mol, and the PI bond energy in this molecule is 184 kJ/mol. The standard heat of formation of PI is 334 kJ/mol, and that of I2(g) is 62 kJ/mol. The I2 bond energy is 151 kJ/mol. Calculate the heat of sublimation of PI3[PI3(s) PI3(g)].
$203.7 k \mathrm{~J} / \mathrm{mo}$
Chemistry 102
Chemistry 101
Chapter 9
Thermochemistry
Thermodynamics
Chemical reactions and Stoichiometry
Alejandro E.
November 12, 2020
But why does the answer say its 126.2
Rice University
University of Toronto
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So this question wants us to find the Delta H sublimation of P ay three. So that's P ay three solid to p ay three gas. And so we know that this Delta H of sublimation is equal to the Delta H of formation of P ay three gas minus the delta H of formation of P ay three solid and so were given this second value, it's negative. Twenty four point seven Killer. Jules Permal We just need to find this first value, and then we can complete this equation. And so to find this first value, the first thing we're going to do is write out our equation of interest. So that would be P I gas plus I to gas form's P ay three gas. And so the first thing we can do is determine the Delta h of this reaction using average bond energies. So that would be the sum of the ages of Bond's broken minus the sum of the ages off bonds formed. And that is going to be equal to the P I Bond plus Thie II bond minus three times the P I bond. And so doing this we have one eighty four plus one fifty one minus three times one eighty four. And that gives us negative to seventeen Killa, Jules, Permal and all of these values air given in the problem for the bond energy of the P I bond, the bond energy of the eye I bond and the bond energy of the P A bond again. So this is our delta h of this reaction. And we also know that the Delta H off this reaction is going to be equal to the entropy of formation of the P I three gas minus the entropy of formation of P I gas minus the entropy of formation off to gas just based on a simple products minus reactant ce. And so we now know all of these values except for the entropy of formation of the P ay three gas, which is what we're interested in. So we take our negative to seventeen killer Jules Permal that equals the entropy of formation of the P ay three gas. And then we subtract and papi information off P I, which is three thirty four killer Jules per mall and then subtract the entropy information of the I too, which is sixty two killer jewels for more. And that gives us an entropy of formation for P I three gas of one seventy nine killer Jules Permal. So now that we have that value, we can go back to our original equation, which was dealt H sublimation equals the entropy of formation of P ay three gas minus the MPA p of formation of P ay three solid. And that gives us now we have both of these values. We just found our entropy information of P I gas to be one seventy nine killer Jules Permal and we know our entropy. A formation off ps three solid is negative. Twenty four point seven Killer Jules per mall. And so that gives us on an therapy of sublimation to be two or three point seven killer Jules Permal. And that is our final answer.
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