00:01
Problem tests some basic concepts of celestial coordinates in rightecential declination, and also a little bit about parallax and angles of measurement.
00:21
And so starting off, you have alpha centauri and proxima centauri, and so you want to find there the difference, in their right ascensions and declinations.
00:37
That's how you find the angular separation.
00:39
So delta alpha right ascension difference is the difference between proximate centauri's right ascention alpha p minus alpha centauri alpha a and declination difference is similar, declination of one minus declination of the other.
01:00
And then we use equation 8 to find the relative separation.
01:06
This is part a.
01:08
We use equation 8, which is delta theta squared, is equal to delta alpha times cosine of one of these declinations squared plus delta, delta squared.
01:25
So delta alpha, as it turns out, as you can find out, is nine minutes, 53 .55 seconds.
01:33
Let's convert that to degrees.
01:36
So this is 9 .895 minutes.
01:43
And then you divide by 60 minutes.
01:48
That's one hour.
01:50
And you note that 15 degrees per 15 degrees per hour is what you is the conversion factor there.
02:04
And so this gives you 2 .4731 degrees for delta a for red ascension difference and then delta delta.
02:16
That's declination difference.
02:18
It's two degrees, nine arc seconds and 16.
02:23
2 degrees 9 arc minutes and 16 .2 arc seconds so this is 2 degrees plus 9 plus 9 plus 0 .27 which is which you get by 16 .2 over 60 for the total number of degrees and so this is 2 plus 2 plus 9 .27 which is which you get by 16 .2 over 60 for the total number of degrees and so this is 2 plus 9 .2 7 by 60 and this gives you a difference in the declination of 2 .1545 degrees.
03:03
And then you take delta as just one of those two, either alpha or proxima centauri, and i'm just going to take proxima centauri...