00:01
So in this problem, they give us two different equations here.
00:03
R represents the reaction time, and b represents the breaking distance.
00:08
So in part a of this problem, they want us to come up with a polynomial to represent the total stopping distance.
00:14
Well, think about it.
00:15
You're going to need time to react, and then the time to break.
00:19
So to find the total time it's going to take to stop, we have to take the reaction time, r, and add it to the break time, which is b.
00:28
So we need to add the two polynomials 1 .1x plus 0 .0475 x squared minus 0 .001x plus 0 .23.
00:42
And now we're going to simplify, and i'm going to put this in standard form.
00:46
So i'm going to have my x squared term first, so 0 .0475 x squared.
00:52
Next, i'll combine the x terms.
00:54
So i have 1 .1x minus 0 .001x, minus 0 .001x.
00:58
Which will give us positive 1 .099x, and then we'll bring down the constant term 0 .23.
01:06
So now we have found the polynomial to represent the total stopping distance.
01:12
All right, so now let's move on to part b.
01:14
In part b, they want us to use this result in part a to estimate the value for t for different x values.
01:22
So first, we have when x is 30.
01:25
So if we need to find the total time it's going to take to stop, which is t, all we need to do is substitute 30 in place of x.
01:33
So when i do that, for the first one, we'll have 0 .0475 times 30 squared, plus 1 .099 times 30 plus 0 .23.
01:48
So now, if i were you, i would go to your calculator and just punch this in.
01:53
So you can have 0 .0475 times 30 squared.
01:57
And then you can add 1 .099 times 30 plus 0 .03, or sorry, 0 .23, and that will give us 75 .95.
02:12
So again, this will tell us our total stopping time.
02:18
Next, or stopping distance, i should say...