0:00
All right.
00:01
So the chapter did offer a sentence or two about the fact that under certain conditions, under acidic conditions, your sulfonic acid acid can desulfinate and form benzene again.
00:21
Right.
00:24
So what is the mechanism for that? right.
00:28
So i think the important thing to realize here is that you're breaking a carbon sulfur bonds and you're replacing it with a carbon hydrogen bonds.
00:36
So for starters, where does that hydrogen come from? and what does that mean your electrophile is? so the mechanism is the same with respect to the benzene ring, right? the arrows are going to push the same way.
00:48
But how are you going to get that sotr? h group to become sulfur trioxide again.
00:57
So let's just start from fundamentals.
01:01
So you have this so3.
01:03
I'm going to start drawing it out because it might come in handy in a little bit.
01:08
So the first thing you have to do is, just for the sake of my arrow portion, i'm going to rearrange how i drew the dabobon's in here.
01:20
So, right, so you have to replace that with a proton.
01:23
So you have, you have sulfuric acid.
01:29
I'm trying to make my arrow pushing super clear.
01:35
So that's the sulfuric acid looks like.
01:38
So what you're going to do is you're going to protonate the benzene ring, just like you do normally.
01:44
So you're going to have, but where is that proton going to go? right.
01:48
On which position is your proton going to be on? so you have s.
01:56
03h.
01:57
Where is your proton? you have to put it on the same carbon that your leaving group is on.
02:07
Because, right, so in normal benzene, this is a proton that you deprotonate.
02:11
And then this is usually e, whatever your electrophile is.
02:15
Right.
02:15
So we're just doing that backwards...