00:01
All right, so to solve this problem, i am going to rewrite it in quadratic equation form.
00:08
So i'm going to subtract 132 from both sides.
00:13
And that's going to leave me with n plus n squared minus 132 equals zero.
00:19
I'm going to rewrite this in standard form, a x squared plus bx plus c.
00:26
And now i'm going to factor.
00:27
So i have n squared plus n minus 132 equals 0.
00:34
And i am going to put my parentheses here.
00:38
And because my c term is negative, but my b term is positive, i know that i'm going to have one addition and one subtraction factor.
00:46
And my coefficient of my a term is one.
00:49
So i know i'm just going to have n times n.
00:51
So now i need to factor 132 to see which factor combination is going to give.
00:57
Me a difference of positive 1.
00:59
So this is even.
01:01
So i get 66.
01:05
This is 11 times 6 and this is 2 times 3.
01:10
So i have 2 times 2 times 3 times 11...