Question
The sum of first three terms of a G.P. is 16 and the sum of the next three terms is 128. Determine the first term, the common ratio and the sum to $n$ terms of the G.P.
Step 1
P.) is 16. We can write this as: \[S_3 = \frac{a(r^3 - 1)}{r - 1} = 16\] where \(a\) is the first term and \(r\) is the common ratio. This is our first equation. Show more…
Show all steps
Your feedback will help us improve your experience
Suman Saurav Thakur and 59 other Precalculus educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
In a G.P. the sum of the second and third terms is 6 and the sum of the third and fourth terms is ---12. Find the first term, the common ratio and the sum of the first five terms.
The sum of first three of a G.P. is to the sum of the first six terms as $125: 152$. Find the common ratio of the G.P.
In an increasing G.P., the sum of the first and the last term is 66, the product of the second and the last but one term is 128 , and the sum of all the terms is 126 . How many terms are there in the progression?
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD