00:01
For this question we will assume that the 4 digit number is wx y z where these are the these four variables represent the 4 digits in the number.
00:16
Now this question some might argue will be easier to solve with other methods of solving system of equations but since we are using the matrix method here we will solve the entire problem using a matrix method.
00:31
So the first equation we can write here is w plus x plus y plus z because they have said the sum of the digits is 10 so this is equal to 10.
00:42
Now from the next relation given in the question that is two times the sum of the thousands and tens digit number is equal to the sum of the hundreds and one's place digit minus one.
01:00
So if we simplify that relation, we get the equation 2w minus x plus 2y minus z is equal to minus 1.
01:11
Now the third relation given is that the 10th place digit is twice the 1th place digit.
01:20
So we'll write 2w minus y is equal to 0.
01:25
Similarly from the fourth relation given that the one's place digit is the sum of the digits in the thousands and the hundreds place we can write on rearranging w plus x minus z is equal to zero now we will write these four equations in matrix form so taking the coefficients and the constant terms we get the matrix one one one ten then then 2 minus 1, 2 minus 1, 2 minus 1, 2.
02:02
Now the coefficient for x is 0 and then minus 1 and 0, here is 0.
02:09
Finally 1 1, 0 and minus 1 and here we get 0.
02:14
So we draw dotted line to separate the coefficients from the constant terms.
02:19
Next we have to do a few row operations to turn this matrix into its row echelon form.
02:25
The first set of row operations we will do is row 2 prime or new row 2 is twice row 1 minus row 2.
02:35
We'll also do a operation on row 3.
02:38
So row 3 prime is twice r1 minus r3.
02:42
Finally we'll do an operation on row 4.
02:45
So row 4 prime is r1 minus r4...