Question
The sum of the squares of the eccentricities of the conics $\frac{x^{2}}{4}+\frac{y^{2}}{3}=1$ and $\frac{x^{2}}{4}-\frac{y^{2}}{3}=1$ is(a) 2(b) $\sqrt{2}$(c) $\frac{\sqrt{7}}{\sqrt{3}}$(d) $\sqrt{7}$
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The first one is an ellipse and the second one is a hyperbola. Show more…
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The sum of the squares of the eccentricities of the conics $\frac{x^{2}}{4}+\frac{y^{2}}{3}=1$ and $\frac{x^{2}}{4}-\frac{y^{2}}{3}=1$ is (a) 2 (b) $\sqrt{2}$ (c) $\frac{\sqrt{7}}{\sqrt{3}}$ (d) $\sqrt{7}$
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