Question
The sum to $n$ terms of the series $\frac{1}{3}+\frac{5}{9}+\frac{19}{27}+\frac{65}{81}+\ldots$ is(A) $n-\frac{\left(3^{n}-2^{n}\right)}{2^{n}}$(B) $n-\frac{2\left(3^{n}-2^{n}\right)}{3^{n}}$(C) $2^{n}-1$(D) $3^{n}-1$
Step 1
We have: \[\frac{1}{3} = 1 - \frac{2}{3}, \frac{5}{9} = 1 - \frac{4}{9}, \frac{19}{27} = 1 - \frac{8}{27}, \frac{65}{81} = 1 - \frac{16}{81}, \ldots\] Show more…
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The sum to $n$ terms of the series $\frac{1}{3}+\frac{5}{9}+\frac{19}{27}+\frac{65}{81}+\ldots$ is (A) $n-\frac{\left(3^{n}-2^{n}\right)}{2^{n}}$ (B) $n-\frac{2\left(3^{n}-2^{n}\right)}{3^{n}}$ (C) $2^{n}-1$ (D) $3^{n}-1$
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