The sum of $n$ terms of an arithmetic progression is given by $S_n = \frac{n}{2}[2a + (n-1)d]$. So, we can write the sums of the $n$ terms of the two progressions as $S_n = \frac{n}{2}[2a_1 + (n-1)d_1]$ and $S_n' = \frac{n}{2}[2a_2 + (n-1)d_2]$.
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