00:01
This question wants us to treat the sun like a black body with the temperature t of 5800 kelvin.
00:06
For part a, it says use equation 34 .2a, which i have written out here to find the peak radiance per unit wavelength.
00:15
And then for part b, it wants us to use 34 .2b, which i also have written out here to find the median wavelength.
00:22
And it wants us to also identify the spectral regions for each.
00:26
So all we have to do is simply plug in the value for the temperature.
00:29
And this is going to give us the value because you'll notice that the numerator is in millimeter times kelvin.
00:35
So the kelvin's are going to cancel out.
00:38
And this is going to give us the value of the wavelength and units of millimeters.
00:43
So this is 500 times 10 to the minus 3 millimeters, or excuse me, not minus 3 millimeters, times 10 to the minus 6 millimeters, which is the equivalent to 500 nanometers.
01:36
So you can look this up and you will find that this is in the somewhere in between the yellow and the green part of the visible spectrum.
01:43
So we can just type yellow slash green...