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Carnegie Mellon University

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Problem 71 Medium Difficulty

The surface of the Sun has a temperature of about 5800 $\mathrm{K}$ . The radius of the Sun is $6.96 \times 10^{8} \mathrm{m} .$ Calculate the total energy radiated by the Sun each second. Assume the emissivity of the Sun is 0.986 .

Answer

$3.85 \times 10^{26} \mathrm{J}$

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Video Transcript

so we can say that the power this total power radiated by the sun would be the stuff in Boston is constant times the surface area times the passivity times the temperature to the fourth power. And this is gonna be equaling 5.669 times 10 to the negative. Eighth watts per meter squared her Calvin to the fourth times. Four pi multiplied by 6.96 times 10 to the eighth meters. Quantity squared times 0.98 brother 0.986 multiplied by 5800 5800 Calvin raised to the fourth power. And so the power would then be equaling 3.85 times 10 to the 26th watts or jewels per second. So the power delivered would be 3.86 times 10 to the 26th jewels for every one second. This would be our final answer. That is the end of the solution. Thank you for watching

Carnegie Mellon University
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