Question
The surface tension of liquid argon is given by $\sigma=\sigma_{0}\left(1-T / T_{c}\right)^{\mathrm{t} .28}$, where $\sigma_{0}=0.038 \mathrm{~N} / \mathrm{m}$ and the critical temperature $T_{c}=151 \mathrm{~K}$. Find the surface entropy per unit area at the triple point, $T=83 \mathrm{~K}$.
Step 1
We are given the surface tension of liquid argon as: $\sigma = \sigma_0 (1 - \frac{T}{T_c})^{0.28}$ where $\sigma_0 = 0.038 \, \text{N/m}$, $T_c = 151 \, \text{K}$, and $T = 83 \, \text{K}$. Show more…
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