00:01
Question is asking us to come up with a method in which we use benzyloxycarbonone group as a protectant group while forming our dipeptide chain or our dipeptide of lysine and isolucine.
00:21
So first we're starting off with lysine.
00:25
We're going to combine it with benzyl chloroformate and we'll form the benzyl oxycarbonil group.
00:34
So now our first amino acid is protected and that was lysine.
00:38
Next, we're going to take the step of adding hydrobomic acid, hbr, as well as ascetic acid, to remove the protectant group, which is the benzyloxycarboneal.
01:17
And then we end up forming co2.
01:24
We've gotten our benzene ring with the bromine, and now we have an isolated lysine structure.
01:34
But now we're going to add an additional, we're going to add an additional amino acid, which is our isolucine to the structure.
01:48
So we will be removing this part and connect or forming our dipeptide bond.
01:58
So isolucine and the side chain of isolucine isolucine is kind of tricky.
02:36
So trying to position in a certain way.
02:44
I don't know if that looks any better, but this is supposed to be isolucine.
02:48
So we do now have our dipeptide bond, and we protect it lysine long enough to get it to react.
02:58
And now what we're going to do is we're actually going to add another amount of the first reactant, which was benzylchloroformate.
03:11
And we're doing that so that then we're actually going to add two equivalents of it so that then we end up protecting both ends of this newly formed dipeptide bond.
03:26
The next question is asking us to show the synthesis of ra.
03:34
So r a, r is tyrosine, and a is alanine...