00:01
Okay, so to solve the system, i'm going to start with equation 3, since it only has one variable.
00:08
Okay, so we're going to multiply two on both sides to get z alone.
00:14
If we multiply two on both sides, 2 over 2 cancels, we're less with c is equal to 4 times 2, which is 8.
00:24
Let me write that down.
00:25
X, y, c is equal to, z is equal to 8.
00:30
Okay, onward to equation two.
00:35
Let's solve for y, since we know z, we have 2 times y, minus 8 is equal to negative 6.
00:45
Add 8 on both sides.
00:49
We get negative 6 plus 8, which is 2...