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The system of equations $\alpha x+3 y+5 z=0,2 x-4 \alpha y+\alpha z=0,-4 x+18 y+7 z=0$ has only trivial solution if $\alpha$ is(a) $-1$ or $-3$(b) 1 or $-3$(c) not equal to 1 or $-3$(d) not equal to $-1$ or 3
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The system of equations $\alpha x+3 y+5 z=0,2 x-4 \alpha y+\alpha z=0,-4 x+18 y+7 z=0$ has only trivial solution if $\alpha$ is (a) $1,-3$ (b) not equal to -3 (c) not equal to 1 (d) not equal to 1 or $-3$
If the system of equations $x+k y+3 z=0,3 x+k y-2 z=0$ $2 \mathrm{x}+3 \mathrm{y}-4 \mathrm{z}=0$ has non trivial solution, then $\left(\mathrm{xy} / \mathrm{z}^{2}\right)=\ldots$ (a) $(5 / 6)$ (b) $-(5 / 6)$ (c) $(6 / 5)$ (d) $-(6 / 5)$
What is the solution of the system? $\left\{\begin{array}{cc}{-3 x+2 y-z=} & {6} \\ {3 x+y+2 z=} & {5} \\ {2 x-2 y-z=} & {-5}\end{array}\right.$ $$ \begin{array}{ll}{\text { A. }(6,5,-3)} & {\text { B. }(1,4,-1)} \\ {\text { C. }\left(0, \frac{17}{5}, \frac{4}{5}\right)} & {\text { D. no solution }}\end{array} $$
Linear Systems
Systems with Three Variables
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