00:01
In this problem, on the topic of kinetics of systems of particles, we are given a system of three particles with the masses given as well as the velocities and external forces.
00:12
We want to find the mass center, the first and second derivative of the mass center, the kinetic energy of the system t, the angular momentum, and the first derivative with respect to time of this angular momentum for this two -dimensional system.
00:28
So firstly to find the mass center, which is r, we know that this mass center r is defined as the sum of the product of the masses times their positions divided by the sum of all their masses.
00:53
And so this is m times a distance of d along unit vector i plus 2m.
01:07
Into 2d times j plus 4m times 1 .5d times k.
01:19
All of this divided by the sum of the masses m plus 2m plus 4m.
01:30
So simplifying, we get this to be d over 7 into unit vector i plus 4x4.
01:45
Plus 6 times unit vector k.
01:49
And so that's the position of the mass center of the system of particles.
01:57
Next we want to find the first derivative of this mass center, r dot, and this is defined as the sum of mi, r i.
02:16
R -i dot over the sum of the masses.
02:20
So this is equal to m into 2v j plus 2m into 3m into 3v k, where v is the velocity of the system plus 4m into v i, all divided by 7m.
03:05
And so calculating this becomes v over 7.
03:11
So this is essentially the velocity of the mass center of the system into 4i plus 2j plus 6k...