00:01
In this problem we have the same contraption we had in the previous problem.
00:05
And we're told that the blocks a, b, and c are at the same initial height.
00:16
We're told that after two seconds, block c relative to a is at minus 280 millimeters.
00:27
So that means it was c is above a by 280 millimeters.
00:36
We're told that at some time the velocity of b with respect to a is 80 millimeters per second.
00:45
And at that same time t1, the position of block a has moved down 160 millimeters and block b has moved down.
00:57
320 millimeters.
01:00
And so our constraint from before we had 2.
01:04
Y .a plus 2 yb plus y c is a constant and then 2 y b minus y b as a constant and then taking derivatives to get the constraints on the velocity and acceleration.
01:18
We're told that the system starts from rest and we'll basically measure the position of each of the blocks from zero when t equals zero so each of the blocks has a position that's related to one -half times the acceleration of block times t squared the first thing they ask is for the acceleration of blocks a and b well we can use the information given here to get that so we know that the position of block a at t1 is a 160 millimeters so we have that position of black b is a hundred and three hundred and thirty two millimeters at t1 and then the relative velocity the relative velocity is the velocity of b with respect to a as a velocity of b which is the acceleration of b times t1 minus the velocity of a minus the velocity of a which is the acceleration of a times t1 and we know that's 80 millimeters per second so this gives us three equations and three unknowns and we can solve that and we get that t1 is four seconds.
02:33
The acceleration of block a is 20 millimeters per second squared and that of block b is 40 millimeters per second squared.
02:43
So those are constants, so that's true for all time.
02:49
And so now they want us to figure out the change in position of d when the velocity of block c is 600 millimeters per second.
02:59
So we can then, if we know the acceleration of a and b, we can get the acceleration of c and d and those are minus 120 millimeters per second squared and 30 millimeters per second squared respectively...