00:01
Using a table to look at the average rate of change between different time intervals, and we will use the equation the average rate of change equals f of b minus f a over b minus a.
00:09
I have the table written out here for us where t is in days, and v of t is in r and a copies per milliliter.
00:23
So the first interval is 411.
00:26
So in this case a is 4 and b is 11.
00:29
So if you look back at the chart, f of b will be 9 .4.
00:33
And f of a will be 53 over 11 minus 4.
00:39
And 9 .4 minus 53 is negative 43 .6, and 11 minus 4 is 7.
00:46
So that divided by 7 will give us negative 6 .23 rna copies per milliliter per day.
01:03
And that is the unit for all four of these intervals.
01:07
Basically all four of these rate of changes.
01:10
The second interval we'll be looking at is 8 .11.
01:14
So again, at 11, f of b is 9 .4, and at 8, it is 18.
01:22
And 11 minus 8 will be the denominator.
01:25
9 .4 minus 18 is negative 8 .6, and 11 minus 8 is 3.
01:33
So negative 8 .6, divided by 3, is about negative 2 .867.
01:39
Again, copies per milliliter per day.
01:49
The third interval is 11 .15.
01:52
So 15 will be f of b this time, and that is 5 .2, and 11 is still 9 .4.
02:00
And then we will have 15 minus 11 as a denominator...