Question

The tail function strips off the first element of a list and returns a list of the remaining elements, so that $$ \text { length }(\operatorname{tail}(\lambda))=\text { length }(\lambda)-1 $$ for any nonempty list $\lambda$. Let $\lambda$ be any list with length $n \geq 1$. Let $1 \leq k \leq n$. Define the function $f$ as follows: $$ f(k, \lambda)=[\text { if } k=1 \text { then } \operatorname{tail}(\lambda) \text { else tail }(f(k-1, \lambda))] . $$ Prove that $k+$ length $(f(k, \lambda))=$ length $(\lambda)$.

   The tail function strips off the first element of a list and returns a list of the remaining elements, so that
$$
\text { length }(\operatorname{tail}(\lambda))=\text { length }(\lambda)-1
$$
for any nonempty list $\lambda$. Let $\lambda$ be any list with length $n \geq 1$. Let $1 \leq k \leq n$. Define the function $f$ as follows:
$$
f(k, \lambda)=[\text { if } k=1 \text { then } \operatorname{tail}(\lambda) \text { else tail }(f(k-1, \lambda))] .
$$
Prove that $k+$ length $(f(k, \lambda))=$ length $(\lambda)$.
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Logic, sets, and recursion
Logic, sets, and recursion
Robert L. Causey 1st Edition
Chapter 3, Problem 46 ↓

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Step 1

In this case, we have $f(1, \lambda) = \text{tail}(\lambda)$. We can see that $k + \text{length}(f(k, \lambda)) = 1 + \text{length}(\text{tail}(\lambda)) = \text{length}(\lambda)$, which satisfies the given equation. Now, let's assume that the equation holds for  Show more…

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The tail function strips off the first element of a list and returns a list of the remaining elements, so that $$ \text { length }(\operatorname{tail}(\lambda))=\text { length }(\lambda)-1 $$ for any nonempty list $\lambda$. Let $\lambda$ be any list with length $n \geq 1$. Let $1 \leq k \leq n$. Define the function $f$ as follows: $$ f(k, \lambda)=[\text { if } k=1 \text { then } \operatorname{tail}(\lambda) \text { else tail }(f(k-1, \lambda))] . $$ Prove that $k+$ length $(f(k, \lambda))=$ length $(\lambda)$.
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